Q. The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?
✅ Correct Answer: (C)
571
Explanation: LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571
Explanation by: Dhruva
LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571