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# 9th Class - Math | Chapter: Heron’s MCQs

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## Q1) Area of triangle is equal to

(A) Base x Height
(B) 2(Base x Height)
(C) 1/2(Base x Height)
(D) 1/2(Base + Height)

(A) 900 cm2
(B) 900√3 cm2
(C) 300√3 cm2
(D) 600√3 cm2

(A) 1320 sq.m
(B) 1300 sq.m
(C) 1400 sq.m
(D) 1420 sq.m

(A) 20√11 cm2
(B) 19√11 cm2
(C) 22√11 cm2
(D) 21√11 cm2

(A) 1000 sq.cm.
(B) 5000 sq.cm.
(C) 9000 sq.cm.
(D) 8000 sq.cm.

(A) 9√15 sq.cm
(B) 6√15 sq.cm
(C) 3√15 sq.cm
(D) √15 sq.cm

## Q7) An isosceles right triangle has area 8 cm². The length of its hypotenuse is

(A) $$\sqrt{32}$$ cm
(B) $$\sqrt{16}$$ cm
(C) $$\sqrt{48}$$ cm
(D) $$\sqrt{24}$$ cm

(A) 10√3 m²
(B) 15√3 m²
(C) 20√3 m²
(D) 100√3 m²

(A) 1322 cm²
(B) 1311 cm²
(C) 1344 cm²
(D) 1392 cm²

(A) 5.196 cm²
(B) 0.866 cm²
(C) 3.496 cm²
(D) 1.732 cm²

(A) 8 cm
(B) 36 cm
(C) 4 cm
(D) 6 cm

(A) 48 cm
(B) 24 cm
(C) 12 cm
(D) 36 cm

(A) 16√5 cm
(B) 10√5 cm
(C) 24√5 cm
(D) 28 cm

## Q14) The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm is

(A) $$\sqrt{15}$$ cm²
(B) $$\sqrt{\frac{15}{2}}$$ cm²
(C) 2$$\sqrt{15}$$5 cm²
(D) 4$$\sqrt{15}$$ cm²

(A) Rs 2.00
(B) Rs 2.16
(C) Rs 2.48
(D) Rs 3.00

(A) 168 cm²
(B) 252 cm²
(C) 336 cm²
(D) 504 cm²

(A) 19.17 sq.cm
(B) 15.17 sq.cm
(C) 20.17 sq.cm
(D) 22.17 sq.cm

(A) 2/27 sq.cm
(B) 2/15 sq.cm
(C) 3/16 sq.cm
(D) 3/14 sq.cm

(A) 9600 sq.m
(B) 9000 sq.m
(C) 9200 sq.m
(D) 8800 sq.m

(A) 1000√3 sq.cm
(B) 1500√3 sq.cm
(C) 1700√3 sq.cm
(D) 1900√3 sq.cm