Q. What will happen when we use void in argument passing?
β
Correct Answer: (B)
It will not return value to its caller
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#include
using namespace std;
int add(int p, int q);
int main()
{
int n = 15, m = 16;
cout << add(n, m) << endl;
return 0;
}
int add(int p, int q )
{
int sum = p + q;
p = 20;
return p + q;
}
#include
using namespace std;
void square (int *p)
{
*p = (*p + 1) * (*p);
}
int main ( )
{
int n = 11;
square(&n);
cout << n;
return 0;
}
#include
using namespace std;
void function(int &p)
{
p = 15;
}
int main()
{
int p = 12;
function(p);
cout << "New value of P is " << p;
return 0;
}
#include
using namespace std;
void copy (int& p, int& q, int& r)
{
p = p * 1;
q = q * 2;
r = r * 3;
}
int main ()
{
int m = 6, n = 3, o = 2;
copy (m, n, o);
cout << "M = " << m << ", N = " << n << ", O = " << o;
return 0;
}
#include <iostream>
using namespace std;
int main()
{
unsigned long num = 56;
cout << num << oct <<" " << num << endl;
return 0;
}