Q. What does the Javascript “debugger” statement do?
✅ Correct Answer: (B)
It acts as a breakpoint in a program.
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var a = Math.max(); var b = Math.min(); print(a); print(b);
Let's go through this carefully.
You have this JavaScript code:
var a = Math.max();
var b = Math.min();
print(a);
print(b);
Now:
Why?
Because:
Thus:
So, the output will be:
-Infinity
Infinity
Therefore, the correct answer is:
(A) -Infinity Infinity
var a = Math.max() < Math.min(); var b = Math.max() > Math.min(); print(a); print(b);
const obj1 = {first: 20, second: 30, first: 50};
console.log(obj1);
function dog() {
print("I am a dog.");
}
dog.sound = "Bark";
const obj1 = {Name: "Hello", Age: 16};
const obj2 = {Name: "Hello", Age: 16};
print(obj1 === obj2);
let n = 24;
let l = 0, r = 100, ans = n;
while(l <= r) {
let mid = Math.floor((l + r) / 2);
if(mid * mid <= n) {
ans = mid;
l = mid + 1;
}
else {
r = mid - 1;
}
}
print(ans);