Q. What is the output of the following program :
Code:i = 0
while i < 5:
print(i)
i += 1
if i == 3:
break
else:
print(0)
Output will be 0 1 2.
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i = 0
while i < 5:
print(i)
i += 1
if i == 3:
break
else:
print(0)
print 'cd'.partition('cd')
print 'abcefd'.replace('cd', '12')
def f(value, values):
v = 1
values[0] = 44
t = 3
v = [1, 2, 3]
f(t, v)
print(t, v[0])
dictionary1 = {'Google' : 1,
'Facebook' : 2,
'Microsoft' : 3
}
dictionary2 = {'GFG' : 1,
'Microsoft' : 2,
'Youtube' : 3
}
dictionary1.update(dictionary2);
for key, values in dictionary1.items():
print(key, values)
dictionary1 = {'GFG' : 1,
'Google' : 2,
'GFG' : 3
}
print(dictionary1['GFG']);
temp = dict()
temp['key1'] = {'key1' : 44, 'key2' : 566}
temp['key2'] = [1, 2, 3, 4]
for (key, values) in temp.items():
print(values, end = "")
data = [2, 3, 9] temp = [[x for x in[data]] for x in range(3)] print (temp)
data = [x for x in range(5)] temp = [x for x in range(7) if x in data and x%2==0] print(temp)
L1 = [1, 2, 3, 4] L2 = L1 L3 = L1.copy() L4 = list(L1) L1[0] = [5] print(L1, L2, L3, L4