Q. What is the output of the following piece of code?
Code:#mod1 def change(a): b=[x*2 for x in a] print(b) #mod2 def change(a): b=[x*x for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)
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#mod1 def change(a): b=[x*2 for x in a] print(b) #mod2 def change(a): b=[x*x for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)
tday=datetime.date.today() print(tday.month())
f = None
for i in range (5):
with open("data.txt", "w") as f:
if i > 2:
break
print(f.closed)